Integrand size = 33, antiderivative size = 65 \[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=-\frac {i \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2}+m,\frac {1}{2},\frac {1}{2} (1-i \tan (e+f x))\right ) (a+i a \tan (e+f x))^m}{f \sqrt {c-i c \tan (e+f x)}} \]
[Out]
Time = 0.12 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.32, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {3604, 72, 71} \[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=-\frac {i 2^m (1+i \tan (e+f x))^{-m} (a+i a \tan (e+f x))^m \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1-m,\frac {1}{2},\frac {1}{2} (1-i \tan (e+f x))\right )}{f \sqrt {c-i c \tan (e+f x)}} \]
[In]
[Out]
Rule 71
Rule 72
Rule 3604
Rubi steps \begin{align*} \text {integral}& = \frac {(a c) \text {Subst}\left (\int \frac {(a+i a x)^{-1+m}}{(c-i c x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\left (2^{-1+m} c (a+i a \tan (e+f x))^m \left (\frac {a+i a \tan (e+f x)}{a}\right )^{-m}\right ) \text {Subst}\left (\int \frac {\left (\frac {1}{2}+\frac {i x}{2}\right )^{-1+m}}{(c-i c x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {i 2^m \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1-m,\frac {1}{2},\frac {1}{2} (1-i \tan (e+f x))\right ) (1+i \tan (e+f x))^{-m} (a+i a \tan (e+f x))^m}{f \sqrt {c-i c \tan (e+f x)}} \\ \end{align*}
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(141\) vs. \(2(65)=130\).
Time = 9.39 (sec) , antiderivative size = 141, normalized size of antiderivative = 2.17 \[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=-\frac {i 2^{-\frac {3}{2}+m} c \left (e^{i f x}\right )^m \left (\frac {e^{i (e+f x)}}{1+e^{2 i (e+f x)}}\right )^m \operatorname {Hypergeometric2F1}\left (1,\frac {3}{2},1+m,-e^{2 i (e+f x)}\right ) \sec ^{-m}(e+f x) (\cos (f x)+i \sin (f x))^{-m} (a+i a \tan (e+f x))^m}{\left (\frac {c}{1+e^{2 i (e+f x)}}\right )^{3/2} f m} \]
[In]
[Out]
\[\int \frac {\left (a +i a \tan \left (f x +e \right )\right )^{m}}{\sqrt {c -i c \tan \left (f x +e \right )}}d x\]
[In]
[Out]
\[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=\int { \frac {{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m}}{\sqrt {-i \, c \tan \left (f x + e\right ) + c}} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=\int \frac {\left (i a \left (\tan {\left (e + f x \right )} - i\right )\right )^{m}}{\sqrt {- i c \left (\tan {\left (e + f x \right )} + i\right )}}\, dx \]
[In]
[Out]
\[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=\int { \frac {{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m}}{\sqrt {-i \, c \tan \left (f x + e\right ) + c}} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=\int { \frac {{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m}}{\sqrt {-i \, c \tan \left (f x + e\right ) + c}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {(a+i a \tan (e+f x))^m}{\sqrt {c-i c \tan (e+f x)}} \, dx=\int \frac {{\left (a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^m}{\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}} \,d x \]
[In]
[Out]